A bag contains 10 red, 6 blue and 4 green jelly beans. If a jelly bean is chosen at random from the bag, what is the probability that it is not blue? A) 1 3 B) 3 10 C) 7 10 D) 7 20

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Answer:

Option C. is the correct option.

Step-by-step explanation:

A bag contains 10 red, 6 blue and 4 green jelly beans.

A jelly bean is chosen at random from the bag then probability that the ball is blue will be = [tex]\frac{\text{Total number of blue balls}}{\text{Total number of balls in the bag}}[/tex]

P(B) = [tex]\frac{6}{20}[/tex]

Now we know that probability that the ball picked from the bag is not blue

= 1 - P(B)

= 1 - [tex]\frac{6}{20}[/tex]

= [tex]\frac{20 - 6}{20}[/tex]

= [tex]\frac{14}{20}[/tex]

= [tex]\frac{7}{10}[/tex]

Therefore, option C. is the correct option.