Question

Hydrogen and oxygen react under a specific set of conditions to produce water according to the equation:
2H2(g)+O2(g) -> 2H2O(g)
How much hydrogen would be required to produce 5.5 mol of water?

And how much oxygen would be required?

Answer 1

Answer:

1. The amount required of H₂ = 11.0 g.

2. The amount required of O₂ = 88.0 g.

Explanation:

• The balanced equation for the mentioned reaction is:

2H₂(g) + O₂(g) → 2H₂O,

It is clear that 2.0 moles of H₂ react with 1.0 mole of O₂ to produce 2.0 moles of H₂O.

Q1: How much hydrogen would be required to produce 5.5 mol of water?

Using cross multiplication:

2.0 mol of H₂ produce → 2.0 mol of H₂O, from stichiometry.

??? mol of H₂ produce → 5.5 mol of H₂O.

∴ the no. of moles of H₂ needed to produce 5.5 mol of water = (2.0 mol)(5.5 mol)/(2.0 mol) = 5.5 mol.

• Now, we can get the mass of H₂ needed to to produce 5.5 mol of water:

mass of H₂ = (no. of moles)(molar mass) = (5.5 mol)(2.0 g/mol) = 11.0 g.

Q2: How much oxygen would be required?

Using cross multiplication:

1.0 mol of O₂ produce → 2.0 mol of H₂O, from stichiometry.

??? mol of O₂ produce → 5.5 mol of H₂O.

∴ the no. of moles of O₂ needed to produce 5.5 mol of water = (1.0 mol)(5.5 mol)/(2.0 mol) = 2.75 mol.

• Now, we can get the mass of O₂ needed to to produce 5.5 mol of water:

mass of O₂ = (no. of moles)(molar mass) = (2.75 mol)(32.0 g/mol) = 88.0 g.

Answer 2

• The amount of hydrogen that will be required is 5.5 moles
• The amount of oxygen that will be required is 2.75 moles

Balanced equation

2H₂(g) + O₂(g) → 2H₂O

From the balanced equation above,

2 moles of H₂O were produced from the reaction of 2 moles of H₂ and 1 mole of O₂

How to determine the mole of hydrogen required

From the balanced equation above,

2 moles of H₂O were produced from the reaction of 2 moles of H₂

Therefore,

5.5 moles of H₂O will also be produced from the reaction of 5.5 moles of H₂

Thus, 5.5 moles of H₂ is needed for the reaction

How to determine the mole of oxygen required

From the balanced equation above,

2 moles of H₂O were produced from the reaction of 1 mole of O₂

Therefore,

5.5 moles of H₂O will be produced from = 5.5 / 2 = 2.75 moles of O₂

Thus, 2.75 moles of O₂ is needed for the reaction

Learn more about stoichiometry:

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