Answer:
C
Step-by-step explanation:
Before multiplying perform the addition in the parenthesis
2 [tex]\frac{1}{6}[/tex] + [tex]\frac{7}{8}[/tex]
Change the mixed number to an improper fraction
2 [tex]\frac{1}{6}[/tex] = [tex]\frac{13}{6}[/tex], thus
[tex]\frac{13}{6}[/tex] + [tex]\frac{7}{8}[/tex]
The fractions require to have a common denominator before adding
The lowest common multiple of 6 and 8 is 24
Multiply numerator/denominator of first fraction by 4
Multiply the numerator/denominator of the second fraction by 3
= [tex]\frac{13(4)}{6(4)}[/tex] + [tex]\frac{7(3)}{8(3)}[/tex]
= [tex]\frac{52}{24}[/tex] + [tex]\frac{21}{24}[/tex] = [tex]\frac{73}{24}[/tex]
Now multiply this result by [tex]\frac{1}{2}[/tex], thus
[tex]\frac{1}{2}[/tex] × [tex]\frac{73}{24}[/tex]
= [tex]\frac{1(73)}{2(24)}[/tex]
= [tex]\frac{73}{48}[/tex]
= 1 [tex]\frac{25}{48}[/tex]
