Question

cone-shaped paperweight has a diameter of 3 inches and a height of 5 inches.

What is the volume of the paperweight?

Use 3.14 for pi.

Enter your answer, as a decimal, in the box.

Answer 1

Answer: $V=11.775\ in^3$

Step-by-step explanation:

You need to use the formula for calculate the volume of a cone. This is:

$V=\frac{1}{3}\pi r^2h$

Where "r" is the radius and "h" is the height.

You know that the diameter of the cone-shaped paperweight is 3 inches. Then, you need to divide the diameter by 2 to find the radius:

$r=\frac{3in}{2}\\\\r=1.5\ in$

Now you know that:

$r=1.5\ in\\h=5\ in\\\pi=3.14$

Substituting these values into the formula $V=\frac{1}{3}\pi r^2h$, you get that the volume of the  paperweight is:

$V=\frac{1}{3}(3.14)(1.5\ in)^2(5\ in)$

$V=11.775\ in^3$

Answer 2

The volume of the paperweight will be 11.76 cubic inches.

What is the volume of a cone?

Let d be the diameter of the base circle and h be the height of the cone.

Then the volume of the cone will be

V = 1/12 x πd² x h

The cone-shaped paperweight has a diameter of 3 inches and a height of 5 inches.

Then the volume of the paperweight will be

V = 1/12 x π(3)² x 5

V = 1/12 x 3.14 x 9 x 5

V = 11.76 cubic inches

More about the volume of the cone link is given below.

https://brainly.com/question/1984638

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