Question

What is the temperature of 0.80 mol of a gas stored in a 275 mL cylinder at 175 kPa?

Answer 1

P*V=n*R*T (Pressure*Volume = mol * 0,082 (constant)* temperature )
175 kPa = 1,727 atm
V=275 ml = 0.275 liters
T=(P*V)/(n*R)=1,727*0.275/0.8*0.082=7,23 Kelvin.

Answer 2

Answer:

              7.23 K

Solution:

Data Given:

                 Moles  =  n  =  0.80 mol

                 Temperature  =  T  =  ??

                  Pressure  =  P  =  175 kPa  =  1.727 atm

                  Volume  =  V  =  275 mL  =  0.275 L

Formula Used:

Let's assume that the gas is acting as an Ideal gas, then according to Ideal Gas Equation,

                  P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for T,

                  T  =  P V / n R

Putting Values,

      T  =  (1.727 atm × 0.275 L) ÷ (0.80 mol × 0.082057 atm.L.mol⁻¹.K⁻¹)

      T  = 7.23 K