Question

The sum of 5 consecutive integers is 110.
What is the fourth number in this sequence?

Answer 1

Answer:

Step-by-step explanation:

let:  x , x+1 , x+2 ,x+3 , x+4 ....( 5 consecutive integers is 110)

x+x+1 +x+2 +x+3+x+4=110

5x +10 = 110

5x =100

x=100/5

x=20

the fourth number in this sequenceis : x+3  so : 23