Respuesta :
Answer:
Option C.
The measure of the complement angle is [tex]18\°[/tex]
Step-by-step explanation:
Let
x-----> the angle
we know that
The complement of an angle is equal to [tex](90-x)\°[/tex]
The supplement of an angle is equal to [tex](180-x)\°[/tex]
we have
The complement of an angle is one-sixth the measure of the supplement of the angle
[tex](90-x)\°=(1/6)(180-x)\°[/tex]
solve for x
[tex](540-6x)\°=(180-x)\°\\ (6x-x)=(540-180)\°\\ (5x)=(360)\°\\ x=72\°[/tex]
Find the measure of the complement angle
[tex](90-x)\° ----> (90-72)=18\°[/tex]
Answer:
Option C. 18
Step-by-step explanation:
Let x be the given angle.
1
6
(180 − x) = (90 − x)
30 −
1
6
x = 90 − x
5
6
x = 60
x = 72°
The supplement angle to 72° is 108°.
The complement angle to 72° is 18°.
