Question

A 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and its temperature changes from 25°C to 175°C. Calculate the specific heat capacity of iron.

Answer 1

Answer:

0.46 J/gC

Explanation:

The specific heat capacity of a material is given by:

$C_s = \frac{Q}{m \Delta T}$

where

Q is the amount of heat absorbed

m is the mass

$\Delta T$ is the variation of temperature

For the piece of iron in the problem:

$m = 15.75 g$

$Q=1086.75 J$

$\Delta T=175 C-25 C=150^{\circ}$

Substituting into the equation,

$C_s = \frac{1086.75 J}{(15.75 g)(150^{\circ}C)}=0.46 J/gC$