Question

Jefferson High School is looking to expand its student parking lot by expanding the existing lot as
shown below.
(Picture Attached)
The size of the new parking lot will be twice the size of the old parking lot. How many feet, x, was the
old parking lot expanded by?
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Answer 1

https://brainly.com/question/3577543

This was already answered.

Answer 2

Answer:

The value of x is 60 ft.

Step-by-step explanation:

The area of a rectangle is

$A=length \times width$

The area of school is

$A=165\times 300=49500$

The area of old lot with school is

$A=(165+75)(300+75)=90000$

The area of old lot without school is

$A_1=90000-49500=40500$

The area of new lot with school is

$A=(165+75+x)(300+75+x)=x^2 + 615 x + 90000$

The area of old lot without school is

$A_2=x^2 + 615 x + 90000-49500=x^2 + 615 x + 40500$

It is given that the area of new parking lot will be twice the size of the old parking lot.

$2A_1=A_2$

$2(40500)=x^2 + 615 x + 40500$

$0=x^2 + 615 x -40500$

$0 = (x - 60) (x + 675)$

$x=60,-675$

The value of x can not be negative. Therefore the value of x is 60 ft.