The area of the square on the third side of the triangle is 11 [tex]units^{2}[/tex]
How to find the area of the square?
Area of square A = [tex]a^{2}[/tex] = 33 [tex]units^{2}[/tex]
Side of square A = a = [tex]\sqrt{33}[/tex] units
Area of square B = [tex]b^{2}[/tex] = 44 [tex]units^{2}[/tex]
Side of square B = b = [tex]2\sqrt{11}[/tex] units
Side of square C = c = [tex]\sqrt{b^{2} - a^{2} } }[/tex]
=[tex]\sqrt{44 - 33}[/tex]
=[tex]\sqrt{11}[/tex] units
Area of square C = [tex]c^{2}[/tex]
= [tex](\sqrt{11}) ^{2}[/tex]
= 11 [tex]units^{2}[/tex]
To learn more about triangles, refer:
https://brainly.com/question/12111621
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