Question

please help !! asap mathematic question worth 12 points

Answer 1

Answer:

1. (d) First F, then D, then C

2. x=16, not extraneous

Step-by-step explanation:

1. Let's solve the given equation and see which steps we need:

$\sqrt{6x + 4} = 8$

Since the X is under a square root, let's raise both sides to their square value.

$\sqrt{6x + 4}^{2}  = 8^{2}$

So we get: 6x + 4 = 64

Next step is to isolate the x factor, so we need to subtract 4 on both sides, to get:

6x = 60

Then to isolate x, we need to divide both sides by 6.

x = 10.

2. Solve for x.  $\sqrt{x + 9} - 4 = 1$

We'll first begin by isolating the square root on its side alone:

$\sqrt{x + 9} = 5$

Then we'll raise each side to its square: x + 9 = 25

Isolate x, to get x = 16

Now, is that solution extraneous or not?

Let's enter 16 in the initial equation and find out:

$\sqrt{x + 9} - 4 = \sqrt{16 + 9} - 4 = \sqrt{25} - 4 = 5 - 4 = 1$

It works, so the solution is not extraneous!