A: outcome has no infection and repair that does not fail
B: outcome has no infection
P(A | B) = P(A and B) / P(B)
For P(A and B) that's the same as P(A). We fail in .03+.14-.01 of the cases, so
P(A) = 1 - (.03+.14-.01) = 1-.16 = 0.84
P(B) = 1 - .03 = .97
P(A|B) = .84/.97 = .866
Answer: 86.6%