Respuesta :
ANSWER
C) 7
EXPLANATION
Let Jane's age be j, and his brother be b.
Jane’s age is 5 years less than 3 times her brother’s age.
Mathematically, we have;
j=3b-5....(1)
Jane’s age is 11 minus her brother’s age.
This is also written mathematically as
j=11-b....(2)
We equate the two equations to get;
11-b=3b-5
Group similar terms:
11+5=3b+b
16=4b
Divide both sides by 4:
b=4.
Therefore Jane's age is
11-4=7 years.
The correct answer is C.
From the information given, Jane's age is 7 years.
Based on the information given, the first equation will be j = 3b - 5 while they second equation will be j = 11 - b.
Therefore, we'll equate both equations which will be:
3b - 5 = 11 - b
3b + b = 11 + 5
4b = 16
b = 16/4
b = 4.
Therefore, Jane's age will be:
j = 11 - b
j = 11 - 4
j = 7
James age is 7 years.
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