When Sharon begin shopping this morning, she have $40. she purchased 5 paperback books and had lunch. The books were all the same price and lunch cost $3.25 she now has $7 left over what was the price of each book
Call the price of a book 'b'. We know that lunch cost $3.25 so let's say [tex]L=3.25[/tex] we also know the total is $40. So we can write: [tex]T=L+5b+7[/tex] or [tex]40=3.25+5b+7[/tex] and then solve for 'b': [tex]29.75=5b[/tex] [tex]b=\frac{29.75}{5} = 5.95[/tex]
