There are 11 letters in "probability"
There are two B's and two I's
11!/(2!2!) = 9,979,200
hope that helps. please name me brainliest
Answer:
8
6
Using all the letters of the word ARRANGEMENT how many different words using all letters at a time can be made such that both A, both E, both R both N occur together .
Hope this helps <3<3<3 Aaliyah
Step-by-step explanation:
