Answer:
[tex]\large\boxed{\dfrac{\frac{-2}{3}}{6}\div\dfrac{\frac{-3}{5}}{10}=\dfrac{50}{27}}[/tex]
Step-by-step explanation:
[tex]\dfrac{\frac{-2}{3}}{6}\div\dfrac{\frac{-3}{5}}{10}=\left(\dfrac{-2}{3}\div6\right)\div\left(\dfrac{-3}{5}\div10\right)=\left(\dfrac{-2\!\!\!\!\diagup^1}{3}\cdot\dfrac{1}{6\!\!\!\!\diagup_3}\right)\div\left(\dfrac{-3}{5}\cdot\dfrac{1}{10}\right)\\\\=\left(-\dfrac{1}{9}\right)\div\left(-\dfrac{3}{50}\right)=\dfrac{1}{9}\cdot\dfrac{50}{3}=\dfrac{50}{27}[/tex]
