Answer:
x = 3
Step-by-step explanation:
Combine the 3 fractions on the left side.
[ note x ≠ - 1, 0, + 1 as this would make the fractions undefined ]
Multiply the numerators/ denominators by the lowest common multiple of
x - 1, x + 1, x , that is x(x - 1)(x + 1), that is
[tex]\frac{x(x+1)}{x(x-1)(x+1)}[/tex] + [tex]\frac{2x(x-1)}{x(x-1)(x+1)}[/tex] - [tex]\frac{3(x-1)(x+1)}{x(x-1)(x+1)}[/tex] = 0
distribute and simplify the numerators
[tex]\frac{x^2+x+2x^2-2x-3(x^2-1)}{x(x-1)(x+1)}[/tex] = 0
[tex]\frac{x^2+x+2x^2-2x-3x^2+3}{x(x-1)(x+1)}[/tex] = 0
[tex]\frac{3-x}{x(x-1)(x+1)}[/tex] = 0
The denominator cannot equal zero only the numerator, hence
3 - x = 0 ⇒ x = 3
