Respuesta :

For this case we have two systems of equations with two unknowns.

[tex]4x + 5y = 7\\3x-2y = -12[/tex]

We multiply the first equation by -3, the second by 4:

[tex]-12x-15y = -21\\12x-8y = -48[/tex]

We add both equations:

[tex]-23y = -69\\y = \frac {69} {23}\\y = 3[/tex]

We substitute the value of y into any of the equations and clear the value of x.

[tex]4x + 5 (3) = 7\\4x + 15 = 7\\4x = 7-15\\4x = -8\\x = \frac {-8} {4}\\x = -2[/tex]

Answer:

(-2,3)

Option A

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