For this case we have two systems of equations with two unknowns.
[tex]4x + 5y = 7\\3x-2y = -12[/tex]
We multiply the first equation by -3, the second by 4:
[tex]-12x-15y = -21\\12x-8y = -48[/tex]
We add both equations:
[tex]-23y = -69\\y = \frac {69} {23}\\y = 3[/tex]
We substitute the value of y into any of the equations and clear the value of x.
[tex]4x + 5 (3) = 7\\4x + 15 = 7\\4x = 7-15\\4x = -8\\x = \frac {-8} {4}\\x = -2[/tex]
Answer:
(-2,3)
Option A