Write the equation of a parabola with vertex (-5,8) and directrix x=2. Show all of your work and put your equation in graphing/vertex form

if anyone can help that'd be amazing :)

Respuesta :

ANSWER

[tex]{(y - 8)}^{2} = - 28(x + 5)[/tex]

EXPLANATION

The equation of a parabola whose axis of symmetry is parallel to the x-axis is given by;

[tex] {(y - k)}^{2} = 4p(x - h)[/tex]

where (h ,k)=(-5,8) is the vertex and p is the focal length.

The focal length is the distance from the focus to the vertex.

This is equal to the distance from the vertex to the directrix.

p=2--5=7

But because the parabola opens in the negative direction of the x-axis, its equation becomes,

[tex]{(y - 8)}^{2} = 4( - 7)(x + 5)[/tex]

[tex]{(y - 8)}^{2} = - 28(x + 5)[/tex]

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