which point is on the graph of the function

Answer:
Step-by-step explanation:
[tex](x,\ y)\\\\\text{Put thecoordinates of the points to the equation of}\ f(x)\ \text{and check the equality}:\\f(x)=\dfrac{1}{2}(2)^x\\\\(0,\ 1)\to x=0,\ y=1\\L=1\\R=\dfrac{1}{2}(2)^0=\dfrac{1}{2}(1)=\dfrac{1}{2}\\\\L\neq R\\\\(0,\ 2)\to x=0,\ y=2\\L=2\\R=\dfrac{1}{2}\\\\L\neq R\\\\\left(1;\ \dfrac{1}{2}\right)\to x=1,\ y=\dfrac{1}{2}\\L=\dfrac{1}{2}\\R=\dfrac{1}{2}(2)^1=\dfrac{1}{2}(2)=1\\\\L\neq R\\\\(1,\ 1)\to x=1,\ y=1\\L=1\\R=1\\\\L=R[/tex]