Answer:
[tex]H.2\sqrt{2}\ cm[/tex]
Step-by-step explanation:
Hello, I think I can help you with this
To solve this you can use the Pythagorean theorem, which states
in a right triangle:
[tex]side\ length^{2}+side\ length^{2}=hypotenuse^{2} \\[/tex]
the hypotenuse is the longest length of the triangle, in this case JK
Step 1
Let
side1= 2 cm
side2= 2 cm
hypotenuse=unknown=JK
isolate the hypotenuse from the equation
[tex]side\ length^{2}+side\ length^{2}=hypotenuse^{2}\\hypotenuse=\sqrt{side\ length^{2}+side\ length^{2}}[/tex]
It's a distance, we'll only take the positive root
put the values into the formula
[tex]hypotenuse=\sqrt{side\ length^{2}+side\ length^{2}} \\hypotenuse=\sqrt{(2\ cm)^{2}+(2\ cm)^{2}}\\hypotenuse=\sqrt{4\ (cm)^{2}+4\ (cm)^{2}}\\hypotenuse=\sqrt{8\ (cm)^{2}} \\hypotenuse=\sqrt{4\ (cm)^{2}*2} \\hypotenuse=\sqrt{4\ (cm)^{2}} \sqrt{2}\\hypotenuse=2\sqrt{2}\ cm[/tex]
the length JK is
[tex]2\sqrt{2}\ cm[/tex]
have a good day
