Question

what s the factor of (x+3)(x+2)

Answer 1

Simplifying (x + 3)(x + 2)
 
Reorder the terms: (3 + x)(x + 2)
 
Reorder the terms: (3 + x)(2 + x)
 
Multiply (3 + x) * (2 + x) (3(2 + x) + x(2 + x)) ((2 * 3 + x * 3) + x(2 + x)) ((6 + 3x) + x(2 + x)) (6 + 3x + (2 * x + x * x)) (6 + 3x + (2x + x2))
 
Combine like terms: 3x + 2x = 5x (6 + 5x + x2)
 
Factor a trinomial. (3 + x)(2 + x)

Final result:
(3 + x)(2 + x)

Answer 2

Basically, don't listen to the other guy, he is making up random stuff, report him.
You can solve this just by multiplying by FOIL
Firsts
Outsides
Insides
Lasts
The firsts of (x+3)(x+2) are x and x, so x*x = x^2
The outsides of (x+3)(x+2) are x and 2, so x*2 = 2x
The insides of (x+3)(x+2) are 3 and x, so 3*x = 3x
The lasts of (x+3)(x+2) are 3 and 2, so 3*2 = 6

Add of of that together, x^2 + 2x + 3x + 6
So the answer is: x^2 + 5x + 6