Respuesta :
Answer:
D. (0,0) satisfies y ≥ x² + x = 4
Step-by-step explanation:
To see if the value pair (0,0), verifies an inequation, we simply have to replace the variables x and y by their values (in this case x=0 and y=0) and see what the final calculation is.
Let's start with the first one:
y ≥ x² + x - 4
If we replace variables by their value, we get:
0 ≥ 0² + 0 - 4
Which is the same as
0 ≥ -4
Which is TRUE, so (0,0) does verify the first inequation.
Let's see for the second one:
y > x² + 2x +1
0 > 0² + 2(0) + 1
0 > 1
Which is FALSE, so (0,0) does NOT verify the second inequation.
Answer:
The correct answer is option D
No. (0, 0) satisfy y ≥ x² + 2x -4 but does not satisfy y > x² + 2x + 1
Step-by-step explanation:
It is given two inequalities
y ≥ x² + 2x -4
y > x² + 2x + 1
Check (0, 0) satisfy the inequalities
1). y ≥ x² + 2x -4
0 ≥ 0² + 2*0 -4
0 ≥ -4
It is true
2). y > x² + 2x + 1
0 > 0² + 2*0 + 1
0 > 1
It is not true
The correct answer is option D
No. (0, 0) satisfy y ≥ x² + 2x -4 but does not satisfy y > x² + 2x + 1