can anybody help me on this
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Answer: second option.
Step-by-step explanation:
Find the distance AE by subtracting AB and DC and dividing by 2:
[tex]AE=\frac{AB-DC}{2}\\\\AE=\frac{24-12}{2}\\\\AE=6[/tex]
Knowing the length of DE and AE, you can apply the Pythagorean Theorem to calculate the distance AD, which would be the hypotenuse of the triangle ADE:
[tex]a=\sqrt{b^2+c^2}[/tex]
Where "a" is the hypotenuse and "b" and "c" are the legs of the triangle.
Then:
[tex]a=AD\\b=AE=6\\c=DE=8[/tex]
Substituting values into [tex]a=\sqrt{b^2+c^2}[/tex] you get that the lenght of AD is:
[tex]AD=\sqrt{6^2+8^2}\\AD=10[/tex]