Answer:
a(n)=1.15[a(n-1)]
Step-by-step explanation:
we know that
[tex]115\%=115/100=1.15[/tex]
Let
a0 -----> the length of the original copy
The first copy is equal to
a1=1.15(a0)
The second copy is
a2=1.15[1.15(a0)] or a2=1.15[a1]
The third copy is
a3=1.15{1.15[1.15(a0)]} or a3=1.15[a2]
therefore
A recursive formula will be
a(n)=1.15[a(n-1)]