Answer:
226.4 m³.
Step-by-step explanation:
The volume of a right cone with a circular base is:
[tex]\displaystyle V = \frac{1}{3} \pi\cdot r^{2}\cdot h[/tex],
where
The radius of the circular base is one-half its diameter.
[tex]\displaystyle r= \frac{1}{2}h=9.3\;\text{m}[/tex].
[tex]\displaystyle V = \frac{1}{3} \pi\cdot r^{2}\cdot h = \frac{1}{3} \pi \times 9.3^{2} \times 2.5 \approx 226.4\;\text{m}^{3}[/tex].