Find the area of the yellow region. Round to the nearest tenth.
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You have a square and four quarter circles with a radius of 4.
The area is
[tex]{ 8}^{2} - 4 \times \frac{90}{360} \pi \times {4}^{2} \\ = 64 - 4 \times \frac{1}{4} \pi \times 16 \\ = 64 - \pi \times 16[/tex]
Put that into your calculator and get the answer.
The area of yellow region is:
13.8 cm^2
The area of the yellow region is the area of square minus 4 times the area of one half semicircle at the corner of the square.
These four half semicircle will form a complete circle.
This means that the area of 4 half semicircles is equal to the area of the circle.
Hence, the area of yellow region is:
Area of square-Area of circle of radius 4 cm.
Also, the radius(r) of circle is: 4 cm.
and the area of circle is given by: [tex]\pi r^2[/tex]
i.e.
[tex]Area\ of\ circle=3.14\times 4^2\\\\i.e. \\\\Area\ of\ circle=50.24\ cm^2[/tex]
Area of square is: [tex]s^2[/tex]
where s is the side length of the square.
Here
[tex]s=8\ cm.[/tex]
Hence,
[tex]Area\ of\ square=8^2\\\\Area\ of\ square=64\ cm^2[/tex]
Hence, Area of yellow region is:
[tex]=64-50.24\\\\=13.76\ cm^2[/tex]
which to the nearest tenth is: 13.8 cm^2