Question

Help? :)

Wan has 22 bulbs of the same shape and size in a box. The colors of and amounts of the bulbs are shown below:

6 blue bulbs
9 red bulbs
7 orange bulbs
Without looking in the box, Wan takes out a bulb at random. He then replaces the bulb and takes out another bulb from the box. What is the probability that Wan takes out an orange bulb in both draws?
7 over 22 multiplied by 7 over 22 equal 49 over 484
7 over 22 multiplied by 6 over 21 equal 42 over 462
7 over 22 plus 6 over 21 equal 279 over 462
7 over 22 plus 7 over 22 equal 308 over 484


A or B? I know he replaced it in the first one, but did he replace it in the second? Hm....

Answer 1

Answer:

A

Step-by-step explanation:

Because he replaced the bulbs it is still the same fraction 7/22 you then multiply it twice cause it is the same possibility of getting orange.

Answer 2

Answer:

7 over 22 multiplied by 7 over 22 equal 49 over 484

Step-by-step explanation:

There are 22 bulbs in the box.

The probability that he got an orange on the first draw is

P (orange) = orange/ total

                  = 7/22

He puts the bulb back so there are still 22 bulbs in the box

The probability that he got an orange on the second draw is

P (orange) = orange/ total

                  = 7/22

To find the probability that he got orange, orange

P (orange, orange) = 7/22 * 7/22

                                =49/484