Respuesta :
The magnetic field is a magnitude that represents the magnetic force. A) B = 2.678 x 10⁻⁵ T /// B) the strength of the coil's field at the center of the tank is smaller than that of the earth.
How to calculate the magnetic field?
The magnetic field is a vectorial magnitude used to represent the intensity of the magnetic force.
To determine the magnetic field, B, we can use the following formula,
B = (μ₀ I N) / 2r
Where,
- B is the magnetic field
- μ₀ is the magnetic permebility in the emptiness
- I is the current intensity, measured in amperes A.
- N is the number of turns
- r is the radius of the solenoid, measured in meters.
The magnetic permeability in the emptiness can be defined as
μ₀ = 4π 10⁻⁷ Tm/A
Units are,
- T = Tesla
- m = meters
- A = amperes
A) What was the magnetic field strength in the center of the tank due to the current in the coil?
Available data:
- N = 100 turns
- D = 2r = 7 m
- r = D/2 = 7/2 = 3.5 m
- I = 1.5 A
Now, we need to replace the terms in the equation,
B = (μ₀ I N) / 2r = (4π 10⁻⁷ Tm/A x 1.5 A x 100) / 7 m
B = 0.00018 T/ 7
B = 2.678 x 10⁻⁵ T
B) Is the strength of the coil's field at the center of the tank larger or smaller than that of the earth?
According to our calculations in poit A), the magnetic field in the center of the tank is
B (tank) = 2.678 x 10⁻⁵ T = 27 μT
Accordin to theoretical framework, the magnetic field of the Earth is
B (Earth) = between 30 and 60 µT
B (tank) < B (Earth)
27 μT < 30 μT
Hence, the strength of the coil's field at the center of the tank is smaller than that of the earth.
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