Respuesta :

khaif

answer is;

b

explanation

magnitude of two points is given by;

√{(x2-x1)^2+(y1-y2)^2}

for RS we have,

√{(b-0)^2+(c-a)^2}

=√{(b)^2+(c-a)^2}

To find the length of a segment you can use the pythagorean theorem: given two points [tex]A=(x_A,y_B),\ B=(x_B,y_B)[/tex] you have

[tex]\overline{AB} = \sqrt{(x_A-x_B)^2+(y_A-y_B)^2}[/tex]

In your case, we have

[tex]\overline{RS} = \sqrt{(x_R-x_S)^2+(y_R-y_S)^2} = \sqrt{(0-b)^2+(a-c)^2} = \sqrt{b^2+(a-c)^2}[/tex]

Note that your exercise seems to suggest the opposite, i.e.

[tex]\overline{RS} = \sqrt{b^2+(c-a)^2}[/tex]

Don't worry: the two numbers are the same. In fact, [tex]a-c[/tex] and [tex]c-a[/tex] are opposite, and opposite numbers are the same when squared (for example, [tex]3^2=(-3)^2=9[/tex])

It had to be so after all: we're simply claiming that the distance between R and S or between S and R is the same..how could it be any different?