Question

The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance between the ball in the room in a shot in which the ball goes exactly in the center of the room? Show your work
Thanks so much in advance ! :))

Answer 1

Answer:

The distance between the ball in the room is $4.2\ in$

Step-by-step explanation:

We know that for a circumference the radius is equal to half the diameter.

$r =\frac{d}{2}$

The diameter of the basketball hoop is 18 inches.

Then the radius of the hoop is:

$r = \frac{18}{2}\\\\r = 9\ inches$

If, the circumference of the ball is 30 inches then the circumference C is:

$C = 2(\pi)r=30$

And the radius of the ball is:

$30 = 2(\pi)r\\\\r =\frac{15}{\pi}$

So the distance between the ball and the ring will be equal to the difference of both radius.

$k = 9-\frac{15}{\pi}\\\\k = 4.2\ in$