Answer:
The answer in the procedure
Step-by-step explanation:
Let
x----> the first number
y----> the second number
we know that
[tex]\frac{x}{y}=\frac{3}{4}[/tex]
so
[tex]y=\frac{4}{3}x[/tex] -----> equation A
[tex]x+y=35[/tex] ----> equation B
substitute equation A in equation B
[tex]x+\frac{4}{3}x=35[/tex]
[tex]\frac{3x+4x}{3}=35[/tex]
[tex]\frac{7}{3}x=35[/tex]
[tex]x=35*3/7=15[/tex]
[tex]y=35-15=20[/tex]