Question

what is the factorization of the trinomial below -x^2+2x+48

Answer 1

Answer:

-(x+6)(x-8)

Step-by-step explanation:

-x²+2x+48

take out the negative

-(x²-2x-48)

factors of 48 with a difference of -2

-8, 6

-(x+6)(x-8)

Answer 2

Answer:

$-(x-8)(x+6)$

Step-by-step explanation:

The given trinomial is

$-x^2+2x+48$

By comparing to $ax^2+bx+c$, we $a=-1,b=2,c=48$.

$ac=-1\times 48=-48$

Two factors of -48 that adds up to 2 are 8,-6.

We split the middle term to obtain;

$-x^2+8x-6x+48$

We now factor by grouping;

$-x(x-8)-6(x-8)$

We factor further to obtain;

$(x-8)(-x-6)$

$-(x-8)(x+6)$