Respuesta :

jg71

[tex]5 \frac{1}{8} + \frac{5}{6} + \frac{5}{12} = x \\ \frac{41}{8} + \frac{5}{6} + \frac{5}{12} = x \\ \frac{123}{24} + \frac{20}{24} + \frac{10}{24} = x \\ \frac{153}{24} = x \\ 6 \frac{9}{24} = x \\ \\ 6 \frac{3}{8} = x[/tex]

Hello!

The answer is:  [tex]\frac{51}{8}[/tex]

Why?

We must remember the way that we can add fractions:

[tex]\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}[/tex]

Let's solve this problem following the next steps:

[tex]5 \frac{1}{8}=\frac{40+1}{8}=\frac{41}{8}[/tex]

Then, adding:

[tex]\frac{41}{8}+\frac{5}{6}=\frac{246+40}{48}=\frac{286}{48}[/tex]

Finally, adding:

[tex]\frac{286}{48} +\frac{5}{12}=\frac{3432+240}{576}=\frac{3672}{576}=\frac{51}{8}[/tex]

Hence,

[tex]5\frac{1}{8} +\frac{5}{6} +\frac{5}{12} =\frac{51}{8}[/tex]

Have a nice day!

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