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A gas of 19 mL at a pressure of 740 mmHg can be expected to change its pressure when its volume changes to 30. mL. Express its new pressure in units of atmospheres.

A. 0.61 atm
B. 1.5 atm
C. 470 atm
D. 590 atm

Respuesta :

The answer is A. 0.61 ATM.

To solve this we assume

that the gas is an ideal gas. Then, we can use the ideal gas equation which is

expressed as PV = nRT. At a constant temperature and number of moles of the gas

the product of PV is equal to some constant. At another set of condition of

temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

P2 = P1V1/V2

P2 = 740mmhg x 19 mL / 30 mL

P2 = 468.67 mmHg = 0.62 atm

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