Respuesta :

Answer:

[tex]x+3y=15[/tex]

Step-by-step explanation:

Formula :- the equation of line which passes through the two points (x1,y1) and (x2,y2)

T-y1/y1-y2=x-x1/x1-x2[/tex]

therefore, the equation of the line which passes through the two points (-6,7) and (-3,6) is

[tex]y1=7,y2=6[/tex]

[tex]x1=-6 ,x2=-3[/tex]

by using above formula

[tex]y-7/7-6=x+6/-6+3[/tex]

[tex]y-7=x+6/-3[/tex]

by cross multiply

[tex]-3y+21=x+6[/tex]

[tex]x+3y=21-6[/tex]

[tex]x+3y=15[/tex]

hence, this is required of line that passes through (-6,7) and (-3,6).

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