Question

A champion bicyclist training in a flat, open area rode 84 kilometers against the wind in 6hours. Riding with the wind, it took her 1 hour to ride the same distance on the return trip. Find the rate of the bicyclist in calm air and the rate of the wind

Answer 1

$84 \div 6 = \times 1$

so 6 ÷ 84=0.0714285714 then ×1 still =0.0714285714. so 0.0714285714 is the calm air and rate of the wind