In this diagram, m ACD =
![In this diagram m ACD class=](https://us-static.z-dn.net/files/d63/05f6a22fe421b3ce6fb020eeb0913e8a.png)
Answer:
m∠ACD=124°
Step-by-step explanation:
∠mACD +m∠DCB=180°
2x+8+x-2=180
3x+6=180
3x=174
x=58
m∠ACD=2x+8=2*58+8=124
m∠ACD=124°
In the diagram, m∠ACD is 124°.
Given:
According to the given diagram.
m∠ACD = 2x + 8
m∠DCB = x - 2
By supplementary angles theorem.
⇒ m∠ACD + m∠DCB = 180°
⇒ 2x + 8 + x - 2 = 180
⇒ 3x + 6 = 180
⇒ 3x = 180 - 6
⇒ 3x = 174
Divide both sides by 3, we get:
⇒ x = 58°
Now put x = 58° in ∠ACD.
⇒ m∠ACD = 2x + 8
⇒ m∠ACD = 2(58) + 8
⇒ m∠ACD = 116 + 8
⇒ m∠ACD = 124°
Therefore, In the diagram, m∠ACD is 124°.
Learn more about the Supplementary Angles here: https://brainly.com/question/13045673
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