Question

F(x)=3x^2+24x+48 What is the discriminant of f? How many distinct real number zeros does f have?

Answer 1

Answer:

Discriminant = 0

Number of real root = 1

Step-by-step explanation:

f(x) = 3x² + 24x + 48

First, we need to find the discriminant.

Discriminant can be found using the formula b² - 4ac.

Discriminant = (24)² - 4(3)(48) = 0

Since the discriminant is 0, it implies that the function has one and only one real root.

Answer 2

The function has only one distinct real number of zeros.

Discriminate :

The discriminate of quadratic function is given as,

                            $D=b^{2}-4ac$

Given function are, $f(x)=3x^{2} +24x+48$

Compare above equation with $ax^{2} +bx+c$

We get ,   $a=3,b=24,c=48$

                   $D=b^{2}-4ac\\ \\D=(24)^{2}-(4*3*48)\\ \\D=576-576=0$

Since, the Discriminate of given function is zero. Therefore, function has only one distinct real number of zeros.

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