Answer:
[tex]\large\boxed{\sqrt{-27}=3i\sqrt3}[/tex]
Step-by-step explanation:
[tex]\sqrt{-27}\\\\\text{In the set of real numbers, this number does not exist.}\\\\\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\sqrt{-27}=\sqrt{(27)(-1)}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt{27}\cdot\sqrt{-1}=\sqrt{9\cdot3}\cdot i=\sqrt9\cdot\sqrt3\cdot i=3i\sqrt3[/tex]
Answer:
it is 3i√3
Step-by-step explanation:
because √-27= √-9(3)= 3(-1)√3= 3i√3
