Use the x-intercept method to find all real solutions of the equation.
x^2-9x^2+23x+15=0
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Answer:
b.[tex]x=1,3,\:or\:5[/tex]
Step-by-step explanation:
The given equation is;
[tex]x^3-9x^2+23x-15=0[/tex]
To solve by the x-intercept method we need to graph the corresponding function using a graphing tool.
The corresponding function is
[tex]f(x)=x^3-9x^2+23x-15[/tex]
The solution to [tex]f(x)=x^3-9x^2+23x-15=0[/tex] is where the graph touches the x-axis.
We can see from the graph that; the x-intercepts are;
(1,0),(3,0) and (5,0).
Therefore the real solutions are:
[tex]x=1,3,\:or\:5[/tex]