Let f(x)=6/−2+2e^−0.3x . What is f(−4) ?
DID THE TEST
ANSWER: 1.3
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Answer:
[tex]f(-4)=1.3[/tex]
Step-by-step explanation:
we have
[tex]f(x)=\frac{6}{-2+2e^{-0.3x}}[/tex]
we know that
f(-4) is the value of the function for x=-4
substitute x=-4 in the function
[tex]f(-4)=\frac{6}{-2+2e^{-0.3(-4)}}[/tex]
[tex]f(-4)=\frac{6}{-2+2e^{1.2}}[/tex]
[tex]f(-4)=1.3[/tex]
Answer:
1.94
Step-by-step explanation:
We substitute -4 into as x in the equation, but first what is e?
e is a term that represents the base of a natural logarithm and is a irrational number, its called Euler's number. e is equivalent to:
[tex]e=2.718[/tex]
We can substitute -4 into the equation
[tex]=6/(-2+2*(2.718^(-0.3*-4)))[/tex]
[tex]=6/(-2+2*(2.718^(1.2)))[/tex]
[tex]=6/(-2+2*2.54)[/tex]
[tex]=6/(3.09)[/tex]
[tex]=1.94
Therefore f(-4)=1.94