Question

Please help!! Double points! write the ratios for sin X and cos X (Image attached)
Will give BRAINLIEST to the person correct answer and please please show your work :))

Answer 1

Answer:

The ratio for sin(X) is $\frac{\sqrt{119} }{12}$

The ratio for cos(X) is $\frac{5}{12}$

Step-by-step explanation:

- The ratio of the sine of a right triangle is:

$sin(\alpha)=\frac{opposite-side}{hypotenuse}$

Since we need the ratio for angle X, $\alpha =X$. From the picture we can infer that the opposite side of X is $\sqrt{119}$. The hypotenuse (the side opposite to the right angle) is 12, so replacing the values:

$sin(X)=\frac{\sqrt{119} }{12}$

- The ratio of the cosine is:

$cos(\alpha)=\frac{adjacent-side}{hypotenuse}$

Similarly, $\alpha =X$, adjacent side = 5, and hypotenuse = 12, so

$cos(X)=\frac{5}{12}$

Answer 2

Answer:

Sin X =√119/12

Cs X = 5/12

Step-by-step explanation:

It is given a right angled triangle.

Points to remember

Sin θ = Opposite side/Hypotenuse

Cos θ = Adjacent side/Hypotenuse

To find the value of Sin X  

Here X is an angle

Opposite side = √119

Hypotenuse = 12

Sin X = Opposite side/Hypotenuse = ZY/XY = √119/12

To find the value of Cos X

Adjacent side of X = 5

Cos X = Adjacent side/Hypotenuse = XZ/XY = 5/12