Solve for A ?
Anyone willing to help me :)
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Answer:
Step-by-step explanation:
Use the cosine law:
[tex]BC^2=AB^2+AC^2-2(AB)(AC)\cos(\angle A)[/tex]
We have:
[tex]BC=a\\\\AB=4\\\\AC=3\\\\m\angle A=32^o\to\cos32^o\approx0.848[/tex]
Substitute:
[tex]a^2=4^2+3^2-2(4)(3)(0.848)\\\\a^2=16+9-20.352\\\\a^2=4.648\to a=\sqrt{4.648}\\\\a\approx2.2[/tex]