What is the m∠N ? Can someone help me :)
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Answer:
Step-by-step explanation:
Use the sine law:
[tex]\dfrac{MO}{\sin(\angle N)}=\dfrac{NM}{\sin(\angle O)}[/tex]
We have:
[tex]MO=18\\\\NM=6\\\\m\angle O=17^o\to\sin17^o\approx0.2924[/tex]
Substitute:
[tex]\dfrac{18}{\sin(\angle N)}=\dfrac{6}{0.2924}[/tex] cross multiply
[tex]6\sin(\angle N)=(18)(0.2924)[/tex]
[tex]6\sin(\angle N)=5.2632[/tex] divide both sides by 6
[tex]\sin(\angle N)=0.8772\to m\angle N\approx61^o[/tex]