Question

In the diagram below P is circumscribed about quadrilateral ABCD. What is the value of x?

Answer 1

Answer:

(A) $x=60^{\circ}$

Step-by-step explanation:

Given: It is given that the circle P is circumscribed about quadrilateral ABCD and ∠BCD=120°.

To find: The value of x

Solution: It is given that the circle P is circumscribed about quadrilateral ABCD and ∠BCD=120°.

Now, we know that the sum of opposite angles in a cyclic quadrilateral is 180°, therefore

${\angle}BAD+{\angle}BCD=180^{\circ}$

substituting the given values, we get

$x+120^{\circ}=180^{\circ}$

$x=60^{\circ}$

Thus, the value of x is 60°.

Hence, option A is correct.