Respuesta :

what does precal mean I don't understand

ANSWER

[tex]\frac{F}{G} ( - 1) = - \frac{ 2}{ 3}[/tex]

EXPLANATION

The given functions are:

[tex]F(x)=2x[/tex]

and

[tex]G(x)= {x}^{2} + 2[/tex]

[tex] \frac{F}{G} (x) = \frac{F(x)}{G(x)} [/tex]

[tex] \frac{F}{G} (x) = \frac{2x}{ {x}^{2} + 2 }[/tex]

Substitute x=-1

[tex] \frac{F}{G} ( - 1) = \frac{2( - 1)}{ {( - 1)}^{2} + 2 }[/tex]

[tex] \frac{F}{G} ( - 1) = \frac{ - 2}{ 1+ 2 }[/tex]

[tex]\frac{F}{G} ( - 1) = - \frac{ 2}{ 3}[/tex]

The first choice is correct.
ACCESS MORE
EDU ACCESS