What is the length of AB¯¯¯¯¯, to the nearest tenth of a centimeter?

Answer:
13.43
Step-by-step explanation:
Law of Sines
x/sin50 = 12/sin42
solve for x and don't forget to put calculator into degree mode
Answer:
[tex]AB\approx13.7cm[/tex] to the nearest tenth.
Step-by-step explanation:
We know two angles and a given side, we can use the sine rule to find the required length.
[tex]\frac{AB}{\sin(50\degree)}=\frac{12}{\sin(42\degree)}[/tex]
We solve for the AB by multiplying both sides by [tex]\sin(50\degree)[/tex].
This implies that;
[tex]AB=\frac{12}{\sin(42\degree)}\times \sin(50\degree)[/tex]
[tex]AB=13.738[/tex]
[tex]AB\approx13.7cm[/tex] to the nearest tenth.