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Write the absolute value equation if it has the following solutions. Hint: Your equation should be written as |x−b| =c. (Here b and c are some numbers.) Chapter Reference b Two solutions: x=2, x=12.

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Answer

[tex]|x-7|=5[/tex]

Explanation

We know that we need to write our absolute value equation as [tex]|x-b|=c[/tex]. We also know that the solutions must be [tex]x=2[/tex] and [tex]x=12[/tex]. We need to replace those values for [tex]x[/tex] in our absolute value equation, so we can create a system of equations and find the values of  [tex]b[/tex] and [tex]c[/tex].

- For [tex]x=2[/tex]

[tex]|x-b|=c[/tex]

[tex]|2-b|=c[/tex] equation (1)

- For [tex]x=12[/tex]

[tex]|x-b|=c[/tex]

[tex]|12-b|=c[/tex] equation (2)

Now we can solve our system of equations step-by-step:

Step 1. Replace equation (1) in equation (2)

[tex]|12-b|=|2-b|[/tex]

Step 2. Square both sides of the equation to get rid of the absolute values

[tex]|12-b|=|2-b|[/tex]

[tex](12-b)^2=(2-b)^2[/tex]

Step 3. Use the square of a binomial formula: [tex](a-b)^2=a^2-2ab+b^2[/tex] and solve the equation.

For our first binomial, [tex](12-b)^2[/tex], [tex]a=12[/tex] and [tex]b=b[/tex]; for our second binomial, [tex](2-b)^2[/tex], [tex]a=2[/tex] and [tex]b=b[/tex]

[tex](12-b)^2=(2-b)^2[/tex]

[tex]12^2-(2)(12)(b)+b^2=2^2-(2)(2)(b)+b^2[/tex]

[tex]144-24b+b^2=4-4b+b^2[/tex]

[tex]144-24b=4-4b[/tex]

[tex]140=20b[/tex]

[tex]b=\frac{140}{20}[/tex]

[tex]b=7[/tex] equation (3)

Step 4. Replace equation (3) in equation (2) to find the value of [tex]c[/tex]

[tex]|12-b|=c[/tex]

[tex]|12-5|=c[/tex]

[tex]|7|=c[/tex]

[tex]c=7[/tex]

Putting it all together we can conclude that our absolute value equation is [tex]|x-7|=5[/tex]

Answer:Ix-7I=5

Hope this helps lol

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