Respuesta :

Answer:

x = [tex] 4 \sqrt { 3 } [/tex]

Step-by-step explanation:

We are given a diagram of a pyramid with a right angled triangle which has [tex]30[/tex]°, [tex]60[/tex]° and [tex]90[/tex]° angles an the hypotenuse is [tex]8cm[/tex].

Since we have a right angled triangle, we can apply sin here:

We know that [tex]sin 60 = \frac{\sqrt{3} }{2}[/tex] so we can write it as

[tex]\frac{\sqrt{3} }{2} = \frac{x}{8}[/tex]

So we get the slant height of x = [tex]4\sqrt{3}[/tex].

Answer:

The slant height of square pyramid = 4√3 m

Step-by-step explanation:

From the figure we can see a square pyramid with lateral edge 8 m

Also the one angle of face triangle is 60° , therefore the face triangle is an equilateral triangle.

Therefore the base is 8 m

To find the slant height

slant height² = Lateral edge² - (base/2)²

    = 8² - (8/2)² = 8² - 4²

    = 64 - 16 = 48

Slant height = √48 = 4√3 m

Therefore slant height of square pyramid =  4√3 m

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